• 3 Reasons to Stay-off Substandard Brake-pads & Rotors

    Posted on: December 17th, 2012 by CHIDON INVESTMENT COMPANY NIGERIA LTD. 1 Comment

    ford-f150-svt-raptor-2010-front-overview-mainThe choices we make when it comes to our cars affects even our basic living and goes a long way to dictate how certain aspects of our lives play out. The same applies when it comes to common decisions like the type of brake-pads we buy, how frequently we change these parts and even capital projects like changing brake rotors or sets of calipers/drums. When it comes to American brands like Jeep, Chrysler, GM, Ford etc, durability is very essential as these products themselves are made to be tougher that most of their counterparts, hence the need for real caution to be exercised when selecting spare-parts like the above mentioned brake parts/adjoining members.

    To further lay more emphasis on the need for proper selection of brake products, I have highlighted a few reasons why the wrong type of products should be avoided. Also in consideration are telltale signs of these sub-standard/poor quality braking products when in use, in case you find yourself unfortunate to have procured any of these products.

    Prone to vibrating: After the fairly cash consuming process of changing your rotors,-probably due to excessive wear/normal aging-one of the easiest ways to spot a badly installed rotor is when your vehicle vibrates unusually than it did before. But if after a double-check and the fault seems to stay same, the main culprit might actually be the new rotors just installed. In the case of Chrysler for instance, original rotors might be valued way over #40,000; but in the open market you might find similar after-market products going for as low #18,000. In this clear case, unsuspecting buyers might simply go for the cheaper and easily accessible parts instead of the original.

    The frequency factor: If you haven’t quite changed the way you drive and the common roads which you ply, but your brake pads get to wear out too often-hence allowing air bubbles penetrate your car’s brake hydraulic system and also affecting braking efficiency-,you at this point have to act. With all these abnormalities in play, the next point of call naturally should be to trace the root problem; if the culprit once again happens to be the type of brake-pad in use, you might consider changing your brake-pad, as well as taking note of the quality this time around. Good brake-pads cost as much as #6000 for most American cars as opposed to commonly available pads obtainable within the #2,500 range .

    Abnormal wearing/heavy squeals: Do you drive a car that squeals underneath at the slightest braking upset? Something is definitely not right! New and/or poorly grounded brake pads can induce these squeals; if that’s the case, retrieving and re-grounding the asbestos surface will reduce such noises. But if this sounds persist, this might be probably due to caliper/rotor interaction or even still the same issue of rotor/brake-pad action; with this reality before you have a potentially bigger problem. As noticed over the years, some types brake rotors disallow wearing or cause excessive pad wearing which comes with a lot of noisy squeals.

    Bottomline, quality braking products can be used for a longer time frame with peace of mind; desist from buying products that might literally risk your life as braking is very crucial to driving.

    You can Contact CHIDON INVESTMENT CO. NIGERIA LTD via 08024289596,08033060093.


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    One Response

    1. Akira says:

      I hope this helpsFor this kind of problem you have to consedir all the forces acting on the car, and use the physics of motion in a circle to calculate the answers you want.The forces on the car are:- its weight w, the normal force N, the frictional force FsThe weight balances the normal force that is N w mgThe horizontal friction force must provide the centripetal force acting towards the centre of the circle (of which the curve is an arc)Using second Law we have Fs ma mv^2/ rThe friction is static because there is no lateral slippage. At the maximum possible speed the frictional force has its maximum value Thus Fs Fsmax us x mg (us here is coefficient of friction)and consequently us x mg mv^2 / r Cancelling out the masses and taking the square roots of both sides of the equation gives (us x g x r) vso max speed v (0.16 x 0.81 x 75 ) 10.85 m/sAt this speed the car is just on the point of slipping .. Any faster, disaster ! You can see that the maximum speed does not depend on the mass of the car, but only on the radius of the curve and the value of the coefficient of friction. Good luck with the exam

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